-36x^2+100=0

Solution for -36x^2+100=0 equation:

-36x^2+100=0

a = -36; b = 0; c = +100;
Δ = b2-4ac
Δ = 02-4·(-36)·100
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*-36}=\frac{-120}{-72}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*-36}=\frac{120}{-72}
=-1+2/3
$